WEBVTT
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we're going to make a rough sketch of this graph
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. So let's start by thinking about the standard function
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. Why equals log based 10 of X. Just
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a rough sketch of that. We know the lager
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with McGrath shape for longer than the growth we know
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this one would go through the 10.10 and also down
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the line. Somewhere down there, it would go
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through the 0.10 1 So what effect does it have
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if we add five to the X, that transformation
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is going to shift. It left five. So
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let's take the graph. We just drew and shipped
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. It left five. Now, remember what we
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just drew has a vertical Assen tote the line X
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equal zero. So if we should that to the
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left five. We now have a vertical Lassen toed
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the line X equals negative five. And if we
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take our X intercept, which was 10 and we
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shifted to the left five, it's now over here
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at negative 40 And if we take our 0.10 1
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and shifted to the left five, we get the
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point 51 So there's a rough sketch of the graph
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, and now for Part B. The same idea
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. Let's start with a parent function. Why equals
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natural log of X? We know it's basic shape
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, Same basic shape as the previous graph also has
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an X intercept at 10 this one goes through the
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point E one. Now what effect does the negative
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have on it that's going to reflect it across the
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X axis? All right, so let's draw that
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. So the point at 10 is still going to
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be at 10 We're just flipping the whole thing upside
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down. The point that was previously E one is
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now e negative one.